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本帖最后由 aa7876 于 2020-4-21 12:47 编辑
ANSWER 2521
Take note that 2, 3, 4, 5, 6, 7, 8, 9, and 10 all go into the LCM which is 2520. So 2520 divided by any number in this group leaves a remainder of 0. So just add 1 to this value to get 2521. This new number will leave a remainder of 1 if you divide it by any number in that group. So 2521 is the smallest number (except for 1) that leaves a remainder of 1 when dividing by these given numbers.
Note: Other values that leave a remainder of 1 can be generated by adding on multiples of 2520. |
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周五拿到Full Licence，开贴庆祝，分享经验。 (2006-3-26) JohnnyWang 
发表于 2020-4-21 12:37
