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楼主:jingwm

ChatGPT吹们要小心了! [复制链接]

发表于 2023-2-14 20:46 |显示全部楼层
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让我不禁想起了马斯克刚开始做,spaceX的火箭回收技术时,明明看到了如外星科技般的一级火箭垂直落地,国内的粉红却嘲笑没个卵用,就连一些准官媒都下场嘲讽。如今国内却在忙着偷学技术也想做出来。
ChatGPT不是完美的,谁也不可能一下子让它完美,它一出世能这样已经很惊艳了,总归是瑕不掩瑜。这时候你们就不用什么马克思主义唯物辩证法里的主要矛盾和次要矛盾了,偏要陷入“你要么完美,要么就是狗屎”的虚假两难逻辑谬误中去,我只能说把你们对中国那种稀烂的技术的耐心和宽容的百分之一拿到chatGPT身上都不至于这样。

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参与人数 3积分 +10 收起 理由
波风鸣城 + 3 我很赞同
厉害 + 4 说的很有道理。
laoqiu + 3 我很赞同

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发表于 2023-2-14 20:55 |显示全部楼层
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LightYear 发表于 2023-2-14 21:46
让我不禁想起了马斯克刚开始做,spaceX的火箭回收技术时,明明看到了如外星科技般的一级火箭垂直落地,国内 ...


”它一出世能这样已经很惊艳了“,我觉得是它是”一出世就会一本正经地胡说八道“,哈哈!

发表于 2023-2-14 21:17 |显示全部楼层
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laoqiu 发表于 2023-2-14 16:02
这只有中国本地化以后才能完善,然而这又意味着只能是个阉割版,跟百度一样。 ...

无解
一个人的沉默,叫思考;所有人的沉默,叫黑暗;

发表于 2023-2-15 09:21 |显示全部楼层
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连小学奥数题也做不对:

题:
盒子里有同样数目的黑球和白球。每次取出8个黑球和5个白球,取出几次以后,黑球没有了,白球还剩12个。一共取了几次?盒子里共有多少个球?
答:
设盒子里原来有 $x$ 个黑球和 $x$ 个白球,共 $2x$ 个球。在每次取球操作中,取出 $8$ 个黑球和 $5$ 个白球,则每次取出 $13$ 个球。因为黑球先于白球被取光,所以取出的次数应该是 $x$ 除以 $8$ 的商,即:

$$\frac{x}{8}$$

取出的总球数为取出的次数乘以每次取出的球数,即:

$$13\times\frac{x}{8}=\frac{13}{8}x$$

因为最后黑球被取光,白球还剩 $12$ 个,所以有:

$$5\times\frac{13}{8}x-8\left\lfloor\frac{x}{8}\right\rfloor=12.$$

其中 $\left\lfloor\frac{x}{8}\right\rfloor$ 表示 $x/8$ 的向下取整。化简上式可得:

$$x=104.$$

因此,盒子里共有 $2x=208$ 个球。最后一次取球操作取出了所有的黑球,因此总共取球的次数为:

$$\left\lfloor\frac{x}{8}\right\rfloor=\left\lfloor\frac{104}{8}\right\rfloor=13.$$

因此,一共取了 $13$ 次,盒子里共有 $208$ 个球。

发表于 2023-2-15 09:22 |显示全部楼层
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不是说这家伙只是一个文科生嘛,别把他当理科生。
之所以会编程,是因为程序也是一门语言。

发表于 2023-2-15 09:30 |显示全部楼层
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本帖最后由 jingwm 于 2023-2-15 11:19 编辑

我把上面的题翻译成英文后它做出来了:

问:
there are same amount of black and white balls in a box. If we take out 8 black balls and 5 white balls at one time, after several times, there is no black ball left, but there are still 12 white balls left. How many balls in the box? And how many times until no black ball left?

答:
Let's start by using algebra to represent the problem. Let b be the initial number of black balls, w be the initial number of white balls, and n be the number of times we draw 8 black and 5 white balls.

After the first draw, we have b-8 black balls and w-5 white balls. Assuming we do this n times, we end up with no black balls left and 12 white balls left, so we have:

b - 8n = 0 (no black balls left)
w - 5n = 12 (12 white balls left)

We also know that there were initially the same number of black and white balls, so b = w. We can substitute b for w in the second equation and solve for n:

b - 5n = 12
b - 8n = 0

Subtracting the second equation from the first, we get:

3n = 12
n = 4

So we drew balls 4 times. Substituting n = 4 back into the equation b - 8n = 0, we get:

b - 8(4) = 0
b = 32

Therefore, there were originally 32 black balls and 32 white balls in the box.



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发表于 2023-2-15 11:54 |显示全部楼层
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昨天我在工作学习版刚刚发了这帖子,没几分钟就被大千了,也不知道触犯了那个管理员的哪根神经。
还说我心胸不开阔,我也是醉了!

发表于 2023-2-15 12:00 |显示全部楼层
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jingwm 发表于 2023-2-15 10:21
连小学奥数题也做不对:

题:

得用英文啊  用中文 出的题语法理解有误 计算就是错误的

发表于 2023-2-15 12:07 |显示全部楼层
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悉尼小苹果 发表于 2023-2-15 13:00
得用英文啊  用中文 出的题语法理解有误 计算就是错误的

你的意思是他不懂中文?那他为啥分析题目好像头头是道的样子,如果不会解,难道不会说一句“对不起请使用英文”吗?

发表于 2023-2-15 12:09 |显示全部楼层
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jingwm 发表于 2023-2-15 13:07
你的意思是他不懂中文?那他为啥分析题目好像头头是道的样子,如果不会解,难道不会说一句“对不起请使用 ...

我猜他目前非英文的都是机翻成英文 估计翻译完了逻辑上会出问题

发表于 2023-2-15 12:10 |显示全部楼层
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我算看透了某些人,我喜欢的东西你就不能说它不好,这是一种什么心态呢?!
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发表于 2023-2-15 12:13 |显示全部楼层
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悉尼小苹果 发表于 2023-2-15 13:09
我猜他目前非英文的都是机翻成英文 估计翻译完了逻辑上会出问题


你根本没看它中文解题思路,完全是错误的!不是翻译的问题。

发表于 2023-2-15 12:16 |显示全部楼层
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jingwm 发表于 2023-2-15 13:13
你根本没看它中文解题思路,完全是错误的!不是翻译的问题。

啊哈哈哈 抱歉 数学不好 看到就自动忽略了 省得费脑细胞

发表于 2023-2-15 12:25 |显示全部楼层
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本帖最后由 jingwm 于 2023-2-15 13:28 编辑

它中翻英的能力还是不错的,比我翻的更专业:

请把下列中文翻译成英文:
盒子里有同样数目的黑球和白球。每次取出8个黑球和5个白球,取出几次以后,黑球没有了,白球还剩12个。一共取了几次?盒子里共有多少个球?

There are an equal number of black and white balls in a box. After taking out 8 black balls and 5 white balls each time, there were no more black balls left and 12 white balls remained. How many times were balls taken out in total? How many balls are in the box in total?

(Note: This is a math problem that involves translation. Here's the solution:)

Let's assume that there are x black balls and x white balls in the box initially.

Each time 8 black balls and 5 white balls are taken out, the number of black balls decreases by 8, and the number of white balls decreases by 5.

After n times of taking out balls, there are no black balls left, and 12 white balls remain. So we have the following equations:

x - 8n = 0 (no more black balls left)
x - 5n = 12 (12 white balls remain)

Solving these equations simultaneously, we get:

x = 40 (there are 40 balls in total)
n = 7 (balls were taken out 7 times in total)


Therefore, there were 40 balls in the box initially, and they were taken out 7 times in total.

这回算式写对了,可是结果错了!

发表于 2023-2-15 12:28 |显示全部楼层
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你能从这些总结归纳出chatgpt的不好,足见你对ai完全没有任何了解,在我眼里,这东西已经具备毁灭人类的要求了,就看啥时候出现了

发表于 2023-2-15 12:33 |显示全部楼层
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澳洲牧羊人 发表于 2023-2-15 13:28
你能从这些总结归纳出chatgpt的不好,足见你对ai完全没有任何了解,在我眼里,这东西已经具备毁灭人类的要 ...

所以我说要小心啊!
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2009年度奖章获得者 2014年度奖章获得者 2015年度奖章获得者

发表于 2023-2-15 12:34 |显示全部楼层
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不懂为什么很多人把chatgpt当作搜索引擎来用,然后嘲笑他的结果不尽如人意

发表于 2023-2-15 12:37 |显示全部楼层
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胡须康 发表于 2023-2-15 13:34
不懂为什么很多人把chatgpt当作搜索引擎来用,然后嘲笑他的结果不尽如人意

不是有人说它马上要取代Google了吗?

发表于 2023-2-15 12:48 |显示全部楼层
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本帖最后由 jingwm 于 2023-2-15 13:51 编辑

不过以后新闻翻译的职业肯定会被ChatGPT取代,举个例子:
英文原文:
Indian tax officers searched the BBC's bureaus in New Delhi and Mumbai on Tuesday, the British broadcaster said, weeks after the government banned as propaganda a BBC documentary critical of Prime Minister Narendra Modi's role in riots in 2002.
The documentary focused on the Hindu nationalist politician's leadership as chief minister of the western state of Gujarat during the riots in which at least 1,000 people were killed, most of them Muslims, though activists put the toll at more than twice that number.
足迹新闻版的翻译
在BBC的纪录片批评印度总理莫迪在2002年骚乱中的作用的几周后,印度税务官员周二搜查了BBC在新德里和孟买的分社。
纪录片侧重于这位印度教民族主义政客在担任西部古吉拉特邦首席部长期间,在至少1000人死亡的社区骚乱中的领导作用。死者大多数是穆斯林,而活动人士则说死亡人数两倍于1000.

ChatGPT的翻译:
周二,印度税务官员搜查了英国广播公司在新德里和孟买的分部,这是印度政府禁止批判纳伦德拉·莫迪总理在2002年暴动中扮演角色的BBC纪录片几周后发生的。
这部纪录片关注了这位印度教民族主义政治家在西部古吉拉特邦担任首席部长期间的领导作用,在那场暴动中至少有1,000人死亡,其中大多数是穆斯林,但活动人士认为死亡人数超过了这个数字的两倍。

2009年度奖章获得者 2014年度奖章获得者 2015年度奖章获得者

发表于 2023-2-15 13:14 |显示全部楼层
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jingwm 发表于 2023-2-15 12:37
不是有人说它马上要取代Google了吗?

说了你就信啊

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最幸福的两个字:吃过
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发表于 2023-2-15 13:32 |显示全部楼层
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看看它自己怎么说:

问:do you think you will replace Google as an effective search engine sooner or later?
答:As an AI language model, my purpose is not to replace Google or any other search engine. Instead, I am designed to help people find information and provide responses to their questions in a conversational way.

Google and other search engines use complex algorithms to crawl and index the web, and they have been refining and improving their search capabilities for many years. While I can provide quick answers to some queries, there are still many cases where a traditional search engine like Google may be more effective.

That being said, I am constantly learning and improving, and I strive to provide accurate and helpful information to users. I believe that there is a place for both search engines and AI language models like myself to coexist and help people find the information they need in different ways.

问:what are you good at compared to the existing search engines?
As an AI language model, I have some unique strengths compared to traditional search engines like Google. Here are a few examples:

Conversational search: I am designed to understand natural language and can respond to queries in a conversational way. This means that I can understand and respond to more complex and nuanced queries, making it easier for users to find the information they need.

Contextual understanding: I have been trained on a wide range of topics and can understand the context of a query to provide more relevant responses. For example, if you ask me "What are some good restaurants near me?", I can use your location to provide personalized recommendations.

Summarization: I can summarize longer pieces of text or provide a brief overview of a topic. This can be helpful when you're looking for a quick answer or don't have time to read a lengthy article.

Personalization: Over time, I can learn from your previous interactions and provide personalized recommendations and responses. This can help to streamline the search process and make it more efficient.

That being said, traditional search engines like Google have their own strengths and are incredibly powerful tools for finding information on the web. Depending on the specific query, it's possible that a traditional search engine may still be more effective.
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发表于 2023-2-15 13:55 |显示全部楼层
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让他自己翻译了上面的英文问答,还不错:

问题:您是否认为您迟早会取代Google成为一款高效的搜索引擎?

答案:作为一个AI语言模型,我的目的并不是取代Google或其他任何搜索引擎。相反,我被设计为以对话方式帮助人们找到信息并回答他们的问题。

Google和其他搜索引擎使用复杂的算法来抓取和索引网页,并且他们已经在不断完善和提高他们的搜索能力多年了。虽然我可以对某些查询提供快速的答案,但在许多情况下,传统的搜索引擎如Google可能更有效。

话虽如此,我不断地学习和改进,并努力为用户提供准确和有用的信息。我相信,搜索引擎和像我这样的AI语言模型可以共存,以不同的方式帮助人们找到他们需要的信息。

问题:与现有的搜索引擎相比,您擅长什么?

答案:作为一个AI语言模型,我与传统的搜索引擎如Google相比具有一些独特的优势。以下是一些例子:

对话式搜索:我被设计为理解自然语言,并以对话方式回答查询。这意味着我可以理解和回答更复杂和微妙的查询,使用户更容易找到他们需要的信息。

上下文理解:我接受了广泛的话题培训,可以理解查询的上下文,提供更相关的响应。例如,如果您问我“我附近有哪些好餐厅?”,我可以使用您的位置提供个性化的建议。

摘要:我可以摘要较长的文本或提供一个主题的简要概述。当你正在寻找一个快速答案或没有时间阅读一篇长文章时,这可能会有所帮助。

个性化:随着时间的推移,我可以从您以前的互动中学习,并提供个性化的建议和响应。这可以帮助简化搜索过程,使其更有效率。

话虽如此,传统的搜索引擎如Google也有自己的优势,并且是在网上找到信息的非常强大的工具。根据具体的查询,传统的搜索引擎可能仍然更有效。

2009年度奖章获得者 2014年度奖章获得者 2015年度奖章获得者

发表于 2023-2-15 14:08 |显示全部楼层
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jingwm 发表于 2023-2-15 13:55
让他自己翻译了上面的英文问答,还不错:

问题:您是否认为您迟早会取代Google成为一款高效的搜索引擎?

所以我说了我不明白为什么要拿取代google搜索引擎最为衡量一个ai应用是否厉害的标准
最幸福的两个字:吃过
最不幸的两个字:瘦过

发表于 2023-2-15 17:57 |显示全部楼层
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天天都在用chatgpt,就像进入了一个新世界,非常好用

发表于 2023-2-15 19:28 |显示全部楼层
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哈哈哈哈,给我看乐了

发表于 2023-2-15 19:52 |显示全部楼层
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人家自己都说了“As an AI language model, my purpose is not to replace Google or any other search engine”,您还偏要说“不是有人说它马上要取代Google了吗?”
选择性的挑选论据啊?
那我说一句我的狗能听懂4种语言,您信不信?
V5
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发表于 2023-2-15 20:32 来自手机 |显示全部楼层
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胡须康 发表于 2023-2-15 15:08
所以我说了我不明白为什么要拿取代google搜索引擎最为衡量一个ai应用是否厉害的标准 ...

所以这玩意到底厉害在哪里,你们老是说很厉害,别的人工智障通过大量存储预设好的问题和答案,靠抓关键字的方法就不厉害吗?是不是计算机算出一个答案但是人类不知道它是怎么算出来的,这就叫厉害了?

发表于 2023-2-15 21:59 |显示全部楼层
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本帖最后由 jingwm 于 2023-2-15 23:13 编辑

Mr. Wang has a box of pencils. If he distributes them equally to 2 students, there will be 1 pencil left over. If he distributes them equally to 3 students, there will be 2 pencils left over. If he distributes them equally to 4 students, there will be 3 pencils left over. And if he distributes them equally to 5 students, there will be 4 pencils left over. What is the minimum number of pencils in the box?
This problem can be solved using the Chinese Remainder Theorem, which is a way to solve a system of congruences.

Let x be the number of pencils in the box. We can set up the following system of congruences:

x ≡ 1 (mod 2)
x ≡ 2 (mod 3)
x ≡ 3 (mod 4)
x ≡ 4 (mod 5)

To solve this system using the Chinese Remainder Theorem, we need to find a number that satisfies all four congruences. First, we can find a number that satisfies the first two congruences:

x ≡ 1 (mod 2)
x ≡ 2 (mod 3)

By inspection, we can see that x = 5 satisfies these congruences. To find a number that satisfies the first three congruences, we can add a multiple of the first two moduli (2 and 3) to x:

x ≡ 5 (mod 2 x 3)
x ≡ 5 (mod 6)

We can see that x = 5 also satisfies this congruence. To find a number that satisfies all four congruences, we can add a multiple of the first three moduli (2 x 3 and 4) to x:

x ≡ 5 (mod 2 x 3 x 4)
x ≡ 5 (mod 24)
x = 24k + 5 for some integer k

Substituting this into the fourth congruence, we get:

24k + 5 ≡ 4 (mod 5)
4k ≡ 4 (mod 5)
k ≡ 1 (mod 5)
k = 5m + 1 for some integer m

Substituting this into the expression for x, we get:

x = 24k + 5
x = 24(5m + 1) + 5
x = 120m + 29

So the minimum number of pencils in the box is 120m + 29, where m is an integer. To find the smallest such number, we can take m = 0, which gives x = 29. Therefore, the minimum number of pencils in the box is 29.

incorrect,please try again

I apologize for the mistake in my previous response. Here's another attempt at solving the problem:

Let x be the number of pencils in the box. We can set up the following system of equations:

x ≡ 1 (mod 2)
x ≡ 2 (mod 3)
x ≡ 3 (mod 4)
x ≡ 4 (mod 5)

To solve this system of equations, we can use the Chinese Remainder Theorem. We first find the least common multiple (LCM) of the moduli, which is 60 (LCM of 2, 3, 4, and 5). Then we can solve the system of equations as follows:

x ≡ 1 (mod 2) ==> x = 2a + 1, where a is an integer
2a + 1 ≡ 2 (mod 3) ==> a ≡ 1 (mod 3) ==> a = 3b + 1, where b is an integer
2(3b + 1) + 1 ≡ 3 (mod 4) ==> b ≡ 0 (mod 2) ==> b = 2c, where c is an integer
2(3(2c) + 1) + 1 ≡ 4 (mod 5) ==> c ≡ 3 (mod 5) ==> c = 5d + 3, where d is an integer

Substituting the values of b and c into the expression for a, and the values of a and c into the expression for x, we get:

a = 3b + 1 = 3(2c) + 1 = 3(2(5d + 3)) + 1 = 30d + 10
x = 2a + 1 = 2(30d + 10) + 1 = 60d + 21

Therefore, the minimum number of pencils in the box is 60d + 21, where d is an integer. To find the smallest such number, we can take d = 0, which gives x = 21. Therefore, the minimum number of pencils in the box is 21.


21/2 remainder is 1, 21/3 remainder is 0, so your answer is wrong

You are correct, and I apologize for my mistake. Here is another attempt at the solution:

Let x be the number of pencils in the box. We can set up the following system of equations:

x ≡ 1 (mod 2)
x ≡ 2 (mod 3)
x ≡ 3 (mod 4)
x ≡ 4 (mod 5)

From the first equation, we know that x is an odd number. Therefore, we can rewrite the system of equations as:

x ≡ 1 (mod 2)
x ≡ 2 (mod 3)
x ≡ 3 (mod 4)
x ≡ 4 (mod 5)
x ≡ 0 (mod 2)

We added the last equation to ensure that x is even.

We can use the Chinese Remainder Theorem to solve this system of equations. Let M = 2 x 3 x 4 x 5 = 120. Then we can write:

x ≡ 1 (mod 2) ==> x = 2k + 1, where k is an integer
2k + 1 ≡ 2 (mod 3) ==> k ≡ 0 (mod 3) ==> k = 3m, where m is an integer
2(3m) + 1 ≡ 3 (mod 4) ==> m ≡ 3 (mod 4) ==> m = 4n + 3, where n is an integer
2(3(4n + 3)) + 1 ≡ 4 (mod 5) ==> n ≡ 2 (mod 5) ==> n = 5p + 2, where p is an integer

Substituting the values of m, k, and x in terms of n, we get:

m = 4n + 3
k = 3m = 12n + 9
x = 2k + 1 = 24n + 19

Therefore, the minimum number of pencils in the box is 24n + 19, where n is an integer. To find the smallest such number, we can take n = 0, which gives x = 19. Therefore, the minimum number of pencils in the box is 19.


my hint in Chinese: 2、3、4、5的最小公倍数是60

非常感谢您的提示!以下是修正后的答案:

设盒子里的铅笔数量为x。我们可以列出以下方程组:

x ≡ 1 (mod 2)
x ≡ 2 (mod 3)
x ≡ 3 (mod 4)
x ≡ 4 (mod 5)

由于2、3、4、5的最小公倍数是60,我们可以利用中国剩余定理求解。我们可以将方程组改写为:

x ≡ 1 (mod 2)
x ≡ 2 (mod 3)
x ≡ 3 (mod 4)
x ≡ 4 (mod 5)
x ≡ 0 (mod 2)

为了确保x为偶数,我们增加了最后一个方程。

然后,我们可以用中国剩余定理求解该方程组。设M = 60,则:

x ≡ 1 (mod 2) ==> x = 2a + 1, 其中a是整数
2a + 1 ≡ 2 (mod 3) ==> a ≡ 1 (mod 3) ==> a = 3b + 1, 其中b是整数
2(3b + 1) + 1 ≡ 3 (mod 4) ==> b ≡ 0 (mod 2) ==> b = 2c, 其中c是整数
2(3(2c) + 1) + 1 ≡ 4 (mod 5) ==> c ≡ 3 (mod 5) ==> c = 5d + 3, 其中d是整数

将b和c的值代入a的表达式,将a和c的值代入x的表达式,我们得到:

a = 3b + 1 = 3(2c) + 1 = 3(2(5d + 3)) + 1 = 30d + 10
x = 2a + 1 = 2(30d + 10) + 1 = 60d + 21

因此,盒子里最少有60d + 21支铅笔,其中d是整数。为了找到最小的这样的数量,我们可以取d = 0,得到x = 21。因此,盒子里最少有21支铅笔。


Second Round

We can use the Chinese Remainder Theorem to solve this problem. The theorem states that if we have a set of simultaneous congruences of the form:

x ≡ a₁ (mod m₁)
x ≡ a₂ (mod m₂)
...
x ≡ aₙ (mod mₙ)

where m₁, m₂, ..., mₙ are pairwise coprime (i.e., their greatest common divisor is 1), then there exists a unique solution for x modulo the product of the moduli, M = m₁m₂...mₙ.

In this problem, we have four congruences:

x ≡ 1 (mod 2)
x ≡ 2 (mod 3)
x ≡ 3 (mod 4)
x ≡ 4 (mod 5)

The moduli are pairwise coprime, so we can use the Chinese Remainder Theorem to find the unique solution modulo M = 2 x 3 x 4 x 5 = 120.

To solve for x, we first find the inverses of 120/2, 120/3, 120/4, and 120/5 modulo the corresponding moduli:

120/2 ≡ 0 (mod 2), so the inverse of 120/2 modulo 2 is 0.
120/3 ≡ 0 (mod 3), so the inverse of 120/3 modulo 3 is 0.
120/4 ≡ 0 (mod 4), so the inverse of 120/4 modulo 4 is 0.
120/5 ≡ 0 (mod 5), so the inverse of 120/5 modulo 5 is 0.

Next, we can use these inverses to express the congruences in terms of x and the moduli:

x ≡ 0 x 1 x 0 x 0 x 1 (mod 2 x 3 x 4 x 5)
x ≡ 2 x 0 x 2 x 0 x 4 (mod 2 x 3 x 4 x 5)
x ≡ 3 x 3 x 0 x 3 x 3 (mod 2 x 3 x 4 x 5)
x ≡ 4 x 4 x 1 x 4 x 0 (mod 2 x 3 x 4 x 5)

Multiplying out the moduli on the right-hand side, we get:

x ≡ 1 (mod 2)
x ≡ 2 (mod 3)
x ≡ 3 (mod 4)
x ≡ 4 (mod 5)

These are the same congruences we started with, but now the moduli are pairwise coprime. We can solve for x by finding the sum of the right-hand sides of these congruences multiplied by the corresponding inverses:

x = 0 x 1 x 0 x 0 x 1 x 2 + 2 x 0 x 2 x 0 x 4 x 1 + 3 x 3 x 0 x 3 x 3 x 0 + 4 x 4 x 1 x 4 x 0 x 0 (mod 2 x 3 x 4 x 5)

Simplifying:

x = 23 (mod 120)

Therefore, the minimum number of pencils in the box is 23.

WRONG

I'm sorry if my previous answer was incorrect. Can you please clarify which part of my solution is incorrect or provide any additional information that can help me better understand the problem? I'd be happy to try and provide a corrected solution.


23/5 remainder is 3

I apologize for the mistake in my previous answer. You are correct that 23 divided by 5 is 4 with a remainder of 3, not 3 with a remainder of 4. This means that if Mr. Wang distributes the pencils equally among 5 students, there will be 3 pencils left over, not 4.

To solve the problem, we can use the method of finding the least common multiple (LCM) of the remainders. The LCM of 1, 2, 3, and 4 is 12. This means that if Mr. Wang distributes the pencils equally among 12 students, there will be 1 pencil left over, since 23 is one more than a multiple of 12.

We can check the other conditions to make sure they hold. If Mr. Wang distributes the pencils equally among 6 students, there will be 5 pencils left over (since 23 divided by 6 is 3 with a remainder of 5). If he distributes them equally among 4 students, there will be 3 pencils left over, and if he distributes them equally among 3 students, there will be 2 pencils left over.

Therefore, the minimum number of pencils in the box is 23, and if he distributes them equally among 12 students, there will be 1 pencil left over.

23 is one more than a multiple of 12?

Yes, that's correct. When 23 is divided by 12, the result is 1 with a remainder of 11. This means that 23 is equal to 12 times some integer (in this case, 1) plus 11. In other words, 23 is one more than a multiple of 12.

23 is one less than 24 and 24=12x2

You are correct, my previous explanation was not accurate. I apologize for the confusion.

When 23 is divided by 12, the result is 1 with a remainder of 11. This means that 23 can be expressed as 12 times some integer (in this case, 1) plus 11. Therefore, we can say that 23 is one less than the next multiple of 12, which is 24. And as you correctly pointed out, 24 can be expressed as 12 multiplied by 2.

So, the minimum number of pencils in the box is 23, and if he distributes them equally among 12 students, there will be 11 pencils left over.



发表于 2023-2-16 07:33 |显示全部楼层
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董宇辉还是那个董宇辉,知识很丰富,口才很好,人长得不咋样,可突然有一天就红了,有人喜欢得不得了,有人觉得不过是另一个网红。
ChatGPT所用人工智能框架并没有本质飞跃,可就是突然出现,突然吸引了大量关注。
喜欢一个人,可以疯狂,但的确需要保留一丝清醒。
指出不足不是坏事,但吹毛求疵就大可不必。

发表于 2023-2-16 07:35 |显示全部楼层
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看看ChatGPT对它自己的评价,你们认同吗?
缺点:
1 对某些主题的知识有限:我只能回答我曾经接受过的训练数据中包含的知识领域问题,如果问题涉及到我未曾学习过的主题,我可能会无法回答或者给出错误的答案。
2 无法理解人类情感:尽管我能够回答与情感有关的问题,但是我并不能理解人类的情感,包括喜怒哀乐等情感表达。在这方面,我只能根据语言规则和先前接受的训练数据来回答问题。
3 缺乏人类直觉:有些问题涉及到人类的直觉、经验和常识,这对于我来说可能是困难的。尤其是当问题具有多重含义或不够明确时,我的回答可能会存在歧义或不确定性。
4 语言模式受限:虽然我可以理解和使用多种语言,但是我的语言模式和表达方式仍然受到固定模式的限制。这意味着我的回答可能会显得有些呆板或者不够自然。
5 缺乏主动学习能力:我只能根据训练数据进行学习和回答问题,无法像人类一样通过主动学习来获取新的知识和技能。这意味着我需要人类提供足够的数据和反馈,才能不断改进我的表现。

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